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1. Assertion (A): Diameter of the chamber in a firearm is slightly greater than the diameter of the cartridge to be fired.
Reason (R): It accommodates the expansion of the cartridge case during the firing process.
- (A) is true, but (R) is false
- (A) is false, but (R) is true
- Both (A) and (R) are false
- Both (A) and (R) are true
Answer
Answer: (4) Both (A) and (R) are true
2. Pistols like the 9 mm Browning pistol are generally semi-automatic. In these pistols, which of the following is true at the instant of their firing?
- The bolt is not locked to the barrel during firing, then the fired cartridge case and bolt both move backwards for unloading and reloading.
- The bolt is locked to the barrel. First it gets unlocked from the barrel and then the fired cartridge case and bolt both move backwards for unloading and reloading.
- Bolt is locked to barrel. Both move backwards and get separated when the pressure in the cartridge case reduces to a safe value. Then the process of unloading and reloading takes place.
- Bolt is locked to barrel. Both move backwards to the full extent. Then the automatic mechanism of long recoil operation takes place.
Answer
Answer: (3) Bolt is locked to the barrel. Both move backwards and get separated when the pressure in the cartridge case reduces to a safe value. Then the process of unloading and reloading takes place.
3. The internal cross-sectional diameter of the barrel of a 10-bore gun is
- More than that of 12-bore gun
- Less than that of 12-bore gun
- More than that of 8-bore gun
- Less than that of 20-bore gun
Answer and Explanation
Answer: (1) More than that of 12-bore gun
Explanation:-> Bore 10: 19.69 cm or 0.775 inches
-> Bore 11: 19.07 cm or 0.751 inches
-> Bore 12: 18.53 cm or 0.729 inches
Note: As the bore number increases the internal cross-sectional diameter decreases.
4. The cutting of barrel length in shotgun causes:
- Decrease in dispersion of pellets
- Increase in dispersion of pellets
- No change in dispersion of pellets
- Distortion of pellets
Answer
Answer: (2) Increase in dispersion of pellets
5. The angle of rifling (θ), pitch of rifling (l) and calibre of a rifle (d) are connected by the following relation:
- d = l/π tan θ
- d = l/π cot θ
- l = d/π tan θ
- l = d/π cot θ
Answer and Explanation
Answer: (1) d = l/π tan θ
Explanation: Read and solve more MCQs related to Rifling Twist
6. The formula for calculating the correct rate of twist for firearm was given by:
- Gaspard Kollner
- George Greenhill
- Greener
- Minie
Answer and Explanation
Answer: (2) George Greenhill
Explanation: George Greenhill was a mathematician at Emmanuel College of England who developed the formula for the calculation of rifling twisting.
7. The formula “(150 x (bullet diameter)2)/bullet length in inches” is used to determine :
- The rate of twist for rifling
- To determine the weight of bullet
- To calculate the speed of bullet
- To calculate the flight path of bullet
Answer and Explanation
Answer: (1) The rate of twist for rifling
Explanation: George Greenhill was a mathematician at Emmanuel College of England who developed the formula for the calculation of rifling twisting. You can check the George Greenhill Twist formula and other related MCQ from [Rifling Related Forensic MCQs].
8. The bullet velocity of a .303 Mark VII cartridge fired from .303-rifle is 2440 ft/sec and the pitch of rifling is one turn in 10 inches. The rate of spin of the bullet when it leaves the muzzle is approximately:
- 2560 revolutions per second
- 2930 revolutions per second
- 3360 revolutions per second
- 3930 revolutions per second
Answer and Explanation
Answer: (2) 2930 revolutions per second
Explanation: Bullet RPM (Rotation per minute)= MV (muzzle velocity) x 720/Twist Rate (in inches).
Bullet Rate of spin = (2440 ft/sec x 720)/ 10 => 175,680 Rotation per minute => 175680/60 Rotation per second= 2928 RPS.
9. Match the following:
List – I | List – II |
(a) Ordinary shotgun | (i) 31/2 to 41/2 pound |
(b) Pistol | (ii) 3-4 pound |
(c) Revolver Double Action | (iii) 16-20 pound |
(d) Service Rifle | (iv) 6-7 pound |
(a) | (b) | (c) | (d) | |
1. | (i) | (ii) | (iii) | (iv) |
2. | (i) | (iv) | (ii) | (iii) |
3. | (iii) | (iv) | (i) | (ii) |
4. | (ii) | (i) | (iv) | (iii) |
Answer and Explanation
Answer: (1) (i), (ii), (iii), (iv)
Explanation: List-II states the corresponding trigger pull of List-I firearms. By definition, trigger pull is the force exerted on the trigger to release the sear is called trigger-pull.
10. Pressure start curve inside the barrel determines:
(i) Temperature of projectile (ii) Trajectory of projectile (iii) Velocity of projectile (iv) Striking energy of projectile
- (i) and (ii) are correct
- (ii) and (iii) are correct
- (iii) and (iv) are correct
- (ii) and (iv) are correct
Answer and Explanation
Answer: (3) (iii) and (iv) are correct
Explanation: Higher the pressure higher the velocity and striking force.
11. In recoil-operated firearms like a pistol, the automatic mechanism works because of
- Force of recoil of firearm
- Force of recoil acting on the head of the cartridge case
- Force of recoil acting on the recoil plate of firearm
- Force of recoil acting on walls and neck of the cartridge case
Answer
Answer: (2) Force of recoil acting on the head of the cartridge case
12. Which of the following is NOT a factor in measurement of recoil?
- Weight of gun and bullet
- Muzzle blast
- Gases formed inside the cartridge case
- Burning on target
Answer and Explanation
Answer: (4) Burning on target
Explanation: All burnt points can be used to estimate the range of firearm ammunition but not recoil.
13. Which of the following is not a result of rifling?
- Increased speed
- Increased range
- Increased precision
- Increased yaw
Answer and Explanation
Answer: (1) Increased in speed
Explanation:
Rifling decreases speed. This is based on the fact that in smoothbore firearms, they are less resistant to the surface which is far more in the rifled bore. Moreover, the key here is that rifling is done to stabilize the flight path of the bullet. And the speed of the bullet precisely depends on the propelling power of the charge.
-> Increased yaw is also not seen in the rifling. But too much rotation (due to rifling) can also make the bullet overstable which may tear the bullet apart.
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