This post contains questions from the 2021 November NTA UGC NET Paper for Forensic Science Paper along with an answer key and explanation that was held on 28th November 2021.
NTA UGC NET conducted two different papers for Forensic Science. The first one was on 20th November 2021, Shift 2 (already solved), and (2) the Second one was on 28th November 2021, Shift 2 (because of restriction probably Corona, to conduct exams in some states on 20th November). In this article, you’re going to get the explanation for the 28th November Forensic paper.
Attention Users: For systematic learning for the Previous Year NTA UGC NET/JRF Forensic Science question paper (both Paper 2 and 3), please refer to the Index Page of Forensic Science NTA UGC NET/JRF.
28 November 2021 UGC NET Forensic Paper With Answer & Explanations
1. A pistol and a fired cartridge is recovered in a murder case. The class characteristics on the fired ammunition identify the make, that is, one in twenty; model, that is, one on five of the firearm. three characteristic marks are also observed on the base of the cartridge case from the breech face of the firearm. The chance of occurrence of these marks ever found to be one in ten thousand each, from the data. Find the probability of the identity of the fired cartridge to be fired with the above pistol
- 1/1012
- 1/1013
- 1/1014
- 1/1015
Answer and Explanation
Answer: (3) 1/1014
Explanation: Following are given probabilities:
-> Probability of class characteristics of fired ammunition: 1/20
-> Probability of class characteristics of firearm: 1/5
-> Probability of each mark (identification standard): 1/104
-> So, for three marks (so for 3 marks= 1/1012)
-> So, the probability of fired cartridge to be fired with a pistol= 1/20 x 1/5 x 1/1012
=> 1/1014
2. Who in his book “A History of the Indian Medical Service” wrote that “a very important part of a civil surgeon’s duties is the performance of medico‐legal post mortem”
- Lt Col C. Newcomb
- Sir William Herschel
- Dr. John Moses
- Lt Col D.G.Crawford
Answer and Explanation
Answer: (4) Lt Col D.G.Crawford
Explanation:
-> This book refers to various laws and regulations, meetings, and policy decisions pertaining to the British Indian Medical Service.
-> It specifies the formation of medical boards in presidencies, the appointment of in-charges, changes during wartime, etc.
3. In which year was the Coroner’s Act, 1871 replaced in India?
- 1997
- 1998
- 1999
- 2000
Answer and Explanation
Answer: (3) 1999
Explanation: Presently, there is no coroner system in India.
-> It was abolished in 1999 when the Coroner’s Act was repealed.
-> The last city in India to have a coroner system was Bombay (Mumbai).
4. Which section under Cr.P.C. 1973 allows for a police inquest?
- Section 176 Cr. P. C 1973
- Section 162 Cr. P. C 1973
- Section 260 Cr. P. C 1973
- Section 174 Cr. P. C 1973
Answer and Explanation
Answer: (4) Section 174 Cr. P. C 1973
Explanation:
-> Section 176 CrPC: Inquiry by Magistrate into cause of death.
-> Section 162 CrPC: Statements to police not to be signed (states their evidentiary value).
-> Section 260 CrPC: Power to try summarily.
5. Disobedience of Court’s summons is an offense punishable under which section of the I. P. C. 1860?
- Section 168 of I. P. C 1860
- Section 172 of I. P. C 1860
- Section 94 of I. P. C 1860
- Section 511 of I. P. C 1860
Answer and Explanation
Answer: (2) Section 172 of I. P. C 1860
Explanation:
-> Section 168 IPC: Public servant unlawfully engaging in trade.
-> Section 94 IPC: Act to which a person is compelled by threats.
-> Section 511 IPC: Punishment for attempting to commit offenses punishable with imprisonment for life or other imprisonments.
6. Open slit interface is used as an interface for which of the undermentioned technique
- HPTLC-MS
- CE-MS
- HPLC-MS
- GC-MS
Answer and Explanation
Answer: (4) GC-MS
Explanation: Open slit interface works as the convenient connection between the GC column and the Mass spectrometer.
-> It provides better chromatographic integrity than that was obtained with the direct introduction of the column into the ion source.
-> Major drawback: conflict against higher mass and higher boiling compounds.
-> Other Interfaces for HPLC/MS are Moving belt (MB), Thermospray (TSP), Electrospray (ESP), and Atmospheric Pressure Chemical Ionization (APCI).
7. In capillary electrophoresis when the ionic strength of a buffer is increased, the zeta potential will_________
- Decrease
- Increase
- Not have any effect
- Depend on the charge of the analyte
Answer and Explanation
Answer: (1) Decrease
Explanation:
-> Zeta potential is the charge that develops at the interface between a solid surface and its liquid medium.
-> Zeta potential is proportional to the charge density on the capillary walls.
-> It is also dependent on the ionic strength of the buffer.
-> An increase in ionic strength results in decreased zeta potential and reduced electroosmotic flow (EOF)
8. Echelle monochromator contains two dispersing elements arranged in a series. The first of these elements is a special type of grating called__
- Echelle grating
- Echellette grating
- Holographic grating
- Prism grating
Answer and Explanation
Answer: (1) Echelle grating
Explanation: There are two types of monochromators; prism and diffraction grating.
-> Prism Monochromators: used to disperse UV, visible, and IR radiation. A common one is Littrow prism (30° prims with a mirrored back, work as 60° prims in Bunsen mount).
-> Diffraction Grating Monochromators: Mostly used in spectrofluorometers and used to disperse UV, visible, and IR radiation by directing through diffraction grated surface (ladder type surface) through transmission grating or reflection grating.
-> Double Monochromator: Combination of two monochromators in series in such a way that the exit slit of the first becomes the entrance slit of the second.
-> Echelle grating was first introduced by G. R. Harrison in 1949.
-> Echelle monochromators contain two different dispersion elements (monochromators). The first is echelle grating and the second is a prism or low dispersion grating.
9. Isotope dilution method is associated with which of the following
- X‐Ray
- N. M. R
- N. A. A
- D. T. A
Answer and Explanation
Answer: (3) N. A. A
Explanation:
-> Isotope dilution is a quantitative method of NAA, based on using a known amount of radioactivity-tagged analyte with the measured amount of sample.
-> Used to determine 30 elements (mostly organic) including vitamin D, vitamin B12, sucrose, insulin, penicillin, various amino acids, corticosterone, alcohols, and thyroxine.
10. Prompt emission of X‐Ray by an atom ionized by a higher energy X‐Ray is a type of which of the following phenomena?
- X‐Ray Luminescence
- X‐Ray Fluorescence
- X‐Ray Phosphorescence
- Spontaneous Emission
Answer and Explanation
Answer: (2) X‐Ray Fluorescence
Explanation:
-> X-ray Fluorescence is the prompt emission of an X-ray by an atom ionized by a higher energy X-ray.
-> These fluorescent emissions are specific to a particular element and are virtually independent of its chemical state.
11. What is the Chromosomal location of HLA DQA1?
- 9P
- 8P
- 7P
- 6P
Answer and Explanation
Answer: (4) 6P
Explanation:
-> The HLA-DQA1 locus (formerly called DQα locus) is a member of the human leukocyte antigen (HLA) family which has a large number of genes involved in immune response in humans.
-> HLA-DQA1 locus is located at the HLA gene cluster on chromosome 6.
-> It was helpful for the first forensic SNP-based profiling.
-> The region has a highly polymorphic value to forensics and is loaded at the second exon of the gene.
Source: [Table] Chromosomal location of the various locus
12. ________ is a modified version of the organic extraction method that separates epithelial and sperm cells from vaginal swab
- Reflux extraction
- Soxhlet extraction
- Differential extraction
- Microwave‐assisted extraction
Answer and Explanation
Answer: (3) Differential extraction
Explanation:
-> Differential lysis treatment can be used to separate epithelial cells from sperm cells from vaginal cells and it was first described by Gill et.al (1985).
-> Principle: Sperm nuclei are resistant to lysis by the usual SDS/proteinase k cell extraction method because of solid disulfide brides present in sperm nuclear membranes.
-> When replaced by proteinase k plus solution the reductant dithiothreitol (DTT, e.g. 20 μl of 0.1 m DTT is added to 500 μl of lysis buffer) breaks the disulfide protein bridge which results in the identification of male-specific cells in female predominantly cells.
Source: Molecular Forensics – Page 43 by Ralph Rapley
13. The leuco base form of malachite green can be oxidized by the catalysis of ________ to produce a green colour
- Platelets
- Heme
- Plasma
- RBC
Answer and Explanation
Answer: (2) Heme
Explanation:
-> Malachite green is a triphenylmethane dye.
-> Leuco base form of malachite green is colorless but when get oxidized by the catalysis of heme produces a green color in acid condition with hydrogen peroxide as oxidant.
Check Reaction involved: Reaction of Leucomalachite Green Assay.
14. Which of these light sources is used commonly for the visual examination of semen stains?
- Tungsten filament lamp
- Hollow Cathode lamp
- Argon laser
- Nernst glower
Answer and Explanation
Answer: (3) Argon laser
Explanation: Dried semen stain can be made visible using irradiated with
-> short wave-long wave UV lamp
-> Argon laser
-> high-intensity alternative light source.
And following are the 3 proposed reasons why semen stains fluorescence.
(1) Conversion of non-protein components to compounds able to fluorescence (proposed by Sensabaugh).
(2) Growth of bacterium Pseudomonas fluorescence on semen stain (proposed by Sensabaugh).
(3) Fluorescence because of the presence of flavins.
15. Regions of chromosomes that are transcriptionally active are known as
- Euchromatin
- Chromatin
- Telomere
- Centromere
Answer and Explanation
Answer: (1) Euchromatin
Explanation:
-> During most of a cell’s life cycle, the chromosomes exist in a linear (unraveled) form that can be transcribed to code for proteins.
-> Euchromatin: Region of chromosomes that are decondensed and transcriptionally active.
● These chromosomes undergo normal chromosome condensation and decondensation
during the cell cycle.
● These regions are enriched in the genes but lack repetitive DNA.
-> Heterochromatin Region: Region of chromosomes that are transcriptionally inactive, such as centromeres, and remain condensed throughout the cell cycle.
● It is dense and contains highly repetitive DNA sequences.
16. The direction of travel of the blood is decided by
- Spine Stain
- Parent Stain
- Both 1 and 2
- Satellite Stain
Answer and Explanation
Answer: (1) Spine Stain
Explanation:
-> Parent Stain is the source point where blood is first projected to the surface.
-> Spine stain is the pointed edge away from the parent stain pointing towards the direction of travel of bloodstains.
-> Satellite Stain is made from smaller bloodstain that originated during the formation of
the parent stain as a result of blood impacting a surface.
17. Wildlife Protection Act, 1972 is an Act of the Parliament of India enacted for the protection of:
- Plants and animals species
- Plants only
- Animals only
- Humans only
Answer and Explanation
Answer: (1) Plants and animals species
Explanation: Four amendments were made until 2023
-> Wildlife Protection Amendment Act 2002: related to punishment
-> Wildlife Protection Amendment Act 2006: related to saving tigers and other endangered species.
-> Wildlife Protection Amendment Act 2013: punishment for hunting and hunting rights of Scheduled Tribes in the Andaman and Nicobar Islands.
-> Wildlife Protection Amendment Act 2021: (Passed by Rajya Sabha on December 8, 2022) seeks to increase the species protected under the law including domesticated endangered species such as elephants. and respective penalties including:
● General violation: up to Rs 25,000 (1972) which changed to up to Rs 1,00,000 (2021 amendment)
● Specially protected animals: at least Rs 10,000 (1972) which changed to at least Rs 25,000.
18. Which one of the following is an example of a herbal antidepressant?
- Hyperforin
- Imipramine
- Citalopram
- Doxepin
Answer and Explanation
Answer: (1) Hyperforin
Explanation:
-> Hypericum perforatum (also called St John’s wort) is a herbaceous plant.
-> It majorly has two active components: hyperforin and hypericin.
-> Imipramine, Citalopram, and Doxepin (other 3 options) all are antidepressants but are chemically made.
Source: Herbal Products: Toxicology and Clinical Pharmacology by Timothy S. Tracy and Richard L. Kingston
19. The natural pyrethrin insecticides are derived from alcohols Cinerolone, Jasmolone, and Pyrethrolone (The question is incomplete in the paper).
- Esters
- Ketones
- Aldehydes
- Phenols
Answer and Explanation
Answer: (1) Esters
Explanation:
-> Pyrethrins are a mixture of six structurally related insecticidal esters formed by a combination of two acids (chrysanthemic acid and pyrethric acid) and three alcohols (pyrethrolone, cinerolone, and jasmolone).
-> Pyrethrins (and synthetic analogue Pyrethroids) are extracted from the Chrysanthemum cineraria folium plant.
-> Toxicity is very low due to its rapid metabolism and is commercially available in form of spray, dust, and mats.
-> Some pyrethrin-based insecticides are bioresmethrin (first available, 1967), allethrin, deltamethrin, decamethrin, cypermethrin, and fenvalerate.
20. Which of the following pH will be selected for good extraction of morphine from urine by using a direct solvent extraction method
- pH 2
- pH 4
- pH 6
- pH 9
Answer and Explanation
Answer: (4) pH 9
Explanation: Various pH values along with buffer for drugs for extraction using direct solvent extraction methods:
-> Barbiturates: eluted at acid pH 2.2 using a citrate buffer
-> Stimulants: eluted at basic pH 11 with a carbonate buffer.
-> Narcotic analgesics and Phenothiazines: eluted at basic pH of 9.3 using a borate buffer.
-> Amphetamines: eluted at pH 9.3 and approx 1/3 of eluant with pH 11.
-> Morphine is an opiate (narcotic) analgesic. So, the pH would be pH 9.3 with borate buffer.
Source: Drug Addiction I: Morphine, Sedative/Hypnotic, and Alcohol
21. ‘Biphasic Effect’ is associated with which of the following
- Alcohol Drinking
- Cocaine abuse
- Charas Smoking
- LSD abuse
Answer and Explanation
Answer: (1) Alcohol Drinking
Explanation:
-> Biphasic effects mean when one substance acts in two different ways as the concentration increases.
-> Alcohol is a great example of a substance that is Biphasic.
-> Drinking a small amount of alcohol gives an uplifting and stimulating effect.
-> Stimulant effects (at lower doses and during rising BACs) include increased motor activity, talkativeness, and euphoria (happiness and positive mood).
Source: Forensic Issues in Alcohol Testing by Steven B. Karch
22. Hawaiian Baby Woodrose plant is associated with which of the following drugs of abuse
- Lysergic acid diethylamide
- Cocaine
- Methcathinone
- Phencyclidine
Answer and Explanation
Answer: (1) Lysergic acid diethylamide
Explanation: Synthesis of Lysergic Acid Diethylamide (LSD) is produced from an ergot alkaloid isolated from certain species of “morning glory” or “Hawaiian Baby Woodrose” plants.
-> Other Names: Argyreia speciosa (scientific name), elephant creeper and woolly morning glory.
23. Which of the following has a street name ‘Liquid Ecstasy’
- Ketamine
- Gamma‐Hydroxybutyric acid
- Fentanyl
- Lysergic acid diethylamide
Answer and Explanation
Answer: (2) Gamma‐Hydroxybutyric acid
Explanation:
-> GHB (gamma hydroxybutyrate) is a depressant.
-> Other names are G, grievous bodily harm (GBH), liquid ecstasy, Liquid X, Liquid E, Georgia Home Boy, cherry meth, blue nitro, and fishies.
24. Find the required twist length in a .303″ rifle, where the length of the projectile is 1.5″
- 10″
- 9″
- 8″
- 7″
Answer and Explanation
Answer: (2) 9″
Explanation: Twist is calculated using the formula; Twist = 150 ×D2 /L where D= bullet diameter in inches and L = bullet length in inches.
-> Given: D= 0.303 and L=1.5″
-> Using equation, Twist= (150 x 0.303 x 0.303)/1.5= 9.18″
=> Closed value to 9.18″ is option (2) 9″
25. Stippling is also known as
- Scorching
- Blackening
- Tattooing
- Singeing
Answer and Explanation
Answer: (3) Tattooing
Explanation: Common wounds in case of wound ballistics:
-> Burning: Effect of hot gases on the skin.
-> Singeing: Effect of hot gases on hair.
-> Searing and Scorching: Intense burning of the skin by flames, usually close contact firing
-> Tattooing: Incomplete combustion of gunpowder which is a consistency of very fine sand. It is also called stippling and peppering ( as resembles black pepper has been spread over the wound). Characteristic of medium-range firearm injury.
-> Identification marker for tattooing: Wipe the suspected skin area with a wet cloth. Black residue on the wound will not vanish.
Jump to Solved Part 2 (26 to 50 questions of 2021, 28 November) through Index Page of Previous Year UGC NTA NET/ JRF Forensic Science Question Paper.
if we have doubt in any question can we ask …..?
Yes, of course.